This post categorized under Vector and posted on July 11th, 2018.

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Since P4 pgraphices through the line of intersection of P1 and P2 P4 contains the line of intersection give by equation [1] above. So any points on the line of intersection will do. Indeed pt (34-1) as you found lies on the line of intersection (this can also be achieved by letting t2 in equation [1] above) and so does (10-1).1-Find an equation of the plane. The plane that pgraphices through (80-1) and contains the line x4-4t y15t z42t-----2-Find an equation of the plane. The plane that pgraphices through the point (-222) and contains the line of intersection of the planes. xy-z3 and 3x-y5z5-----3-Find an equation of the plane.Really dont know what to do here went to a tutor neither did he. Okay first the problem Find the equation of the plane that pgraphices through the line of intersection of the planes x z 2 and

Oct 16 2007 Find the equation of the plane through point (-1 4 2) that contains the line of intersection of the planes 4x - y z - 2 0 and 2x y - 2z - 3 0 By making y t I found the intersecting line equation to be x 710 110 t y t z -45 35 t.Status ResolvedAnswers 5Any point on the intersection line between two planes satisfies both planes Find the equation of a plane that pgraphices through the points (10 2) (-3 5